Question

integration of (e^tanx)/(cos^2)x a=0 b=pie/4

Answer 1

try doing a substitution, u = tan x.

Answer 2

∫ [e^(tan x)] / cos ^ 2 (x) dx, from 0 to pi/4
= ∫ [e^(tan x)] d tan x, from 0 to pi/4
= [e^(tan x)], from 0 to pi/4
= e - 1
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Ideas: (tan x)' = 1/cos^2 (x) and use mental substitution.