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Mathematics
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OpenStudy (anonymous):
Simplify the following expression.
\[\sqrt{-18}\sqrt{-72}\]
14 years ago
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OpenStudy (lgbasallote):
\[\sqrt{(-18)(-72)}\]
can you use a calculator?
14 years ago
OpenStudy (anonymous):
maybe
14 years ago
OpenStudy (anonymous):
I DONT HAVE ONE
14 years ago
OpenStudy (anonymous):
HELP PLEASE
14 years ago
OpenStudy (chris):
I think the question was more - are you allowed to on this problem.
14 years ago
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OpenStudy (lgbasallote):
okay..i'll do this the manual way...
14 years ago
OpenStudy (lgbasallote):
yuppp that's what i meant thanks @chris :D
14 years ago
OpenStudy (chris):
np =). and I think we're assuming not allowed heh.
14 years ago
OpenStudy (zarkon):
\[\sqrt{-18}\sqrt{-72}\neq \sqrt{(-18)(-72)}\]
14 years ago
OpenStudy (lgbasallote):
oh man..made a mistake in one :O
14 years ago
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OpenStudy (anonymous):
WHAT WAS THE MISTAKE
14 years ago
OpenStudy (lgbasallote):
isn;t it @Zarkon ? isn't \[\sqrt{a}\sqrt{b} = \sqrt{(a)(b)}\]?
14 years ago
OpenStudy (zarkon):
if \(a,b\ge 0\)
14 years ago
OpenStudy (lgbasallote):
oh..hmm..yeah..this is imaginary now that i think about it..
14 years ago
OpenStudy (zarkon):
\[\sqrt{-18}\sqrt{-72}\]
\[=i\sqrt{18}\times i\sqrt{72}\]
\[=i^2\sqrt{18}\times \sqrt{72}\]
\[=-\sqrt{18\times 72}\]
\[=-\sqrt{18\times 2\times 36}\]
\[=-\sqrt{36\times 36}=-36\]
14 years ago
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OpenStudy (lgbasallote):
hmm yeah..went pretty careless there..sorry :)
14 years ago
OpenStudy (anonymous):
im confused
14 years ago
OpenStudy (anonymous):
THANKS EVERYONE
14 years ago
OpenStudy (lgbasallote):
\[\sqrt{-a} = i \sqrt{a}\]
he just factored an i..then when i^2..it became -1...my other mistake was the 2 i pulled out..i wrote 4 so my answered doubled..do you get it now?
14 years ago
OpenStudy (anonymous):
YES
14 years ago
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OpenStudy (anonymous):
|dw:1333603586979:dw|
14 years ago
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