A chemist wants to produce 12.00 grams of barium sulfate by reacting a .6000 M BaCl2 solution with excess H2SO as show in the reaction below. What volume of the barium chloride should be used?
BaCl2 + H2SO4 -- BaSO4 +2HCl

Question

A chemist wants to produce 12.00 grams of barium sulfate by reacting a .6000 M BaCl2 solution with excess H2SO as show in the reaction below. What volume of the barium chloride should be used?
BaCl2 + H2SO4 --> BaSO4 +2HCl

anonymous · Answer

Find the moles of BaSO4 first. Then since we know it's a one to one ratio from barium chloride to barium sulfate we can just solve for liters.$${12.00gBaSO_4 \over 233.31 \ grams\  per \ mole }= .05141 moles $$$$Molarity = {moles \over liters} $$$$Liters = {.05141moles \over .6Molarity} =\color{red}{ the \ answer}$$

anonymous · Answer

Thank you so much!

anonymous · Answer

No problem. Remember the answer is in liters and  should probably be expressed in milliliters.

anonymous · Answer

Ok, thanks :)