Question

\[Substitute~~~~~\int\limits {1 \over (3x+4)^2} dx ---->3x+4=u\]

Answer 1

Where are you having problems?
u = 3x +4 => du/3
It's pretty easy..

Answer 2

Can you show the steps of how to integrate it?\[\int\limits {1 \over u^2}dx\] becomes....

Answer 3

Write it as \[\int\limits u^{-2} dx\]

Answer 4

are you able to integrate it?

Answer 5

Yes\[-->{ 1 \over u}\]

Answer 6

But why is the answer 1/-3(3+4) and not 1/3x+4?

Answer 7

sorry, it's -1/u

Answer 8

Why?

Answer 9

\[\int\limits\frac{1}{(u)^{2}} *\frac{du}{3} => \frac{1}{3} \int\limits\frac{1}{u^{2}} \]

Answer 10

You move the 1/3 outside..

Answer 11

then integrate it..

Answer 12

\[\int\limits \sin({1\over3}\pi-{1\over2}x)dx~~~~~~~Why~would~2~go~on~the~outside~instead~of~1/2?\]

Answer 13

Sorry, I don't know, lol. i forgot this...

Someone else should help, lol

Answer 14

Thanks for trying to help anyway! ;D