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Mathematics 15 Online
OpenStudy (anonymous):

prove that gradient of vectorA dot with vector r equals to vectorA for any constant vectorA

OpenStudy (anonymous):

www.mas.ncl.ac.uk/~nas13/mas2104/prob4.pdf just follow this !!

OpenStudy (anonymous):

r(X,Y,Z) where X,Y,Z are functions of(x,y,z) A(a,b,c) A dot r = (aX + bY + cZ) grad(aX + bY + cZ) =(d(aX + bY + cZ)/dx,d(aX + bY + cZ)/dy,d(aX + bY + cZ)/dz) this is not necesarly equal A

OpenStudy (anonymous):

if r is a position vector with coordinates r =(x,y,z) then yes.

OpenStudy (experimentx):

gradient gives the maximum rate of change along the direction of maximum change ... the gradient of a constant vector is zero

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