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\[\int\limits [1/(\sec ^2x \csc ^5x)\]
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\[{1\over\sec^2 x\csc^5 x}=\cos^2x\sin^5x=\cos^2x\sin^4x (\sin x)=\cos^2x(1-\cos^2)^2\sin x\]expand and u-sub\[u=\cos x\implies du=-\sin xdx\]
thanks I got it the answer is (u^3/3)-(2u^5/5)+(u^7/7), am i right?
I don't know, I haven't checked!
one sec, brb
umm, besides missing the minus signs I thin that is right
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remember derivative cos is -sin, so all these u-subs need a -1 in front -(u^3/3)+(2u^5/5)-(u^7/7)
oh ya i see thanks again
welcome :D and don't forget +C !!!
yes thank you
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