i love ham
@amymsmith2121 I'll help you but it'd be an interactive session. Would you respond to my simple questions???
ok
We have \[f(x)=\frac{(x+a)(x+b)}{(x+c)(x+d)}\] You know what is a zero, asymptote and hole???
yes, I do
Tell me???
a hole is a missing part of the graph's points. An asymptote is a line that a graph approaches, but does not intersect
A zero???
Where a function equals the value zero (0).
Great:) So tell me the zeros of this function???
I don't know how I could know that if I only have variables...
We have \[f(x)=\frac{(x+a)(x+b)}{(x+c)(x+d)}\] Put x=-a , see what will you get?
x=-a will make the numerator zero, so f(-a)=0
oohh k
so tell me the other zero ??
b?
correct, can you tell me the asymptote for this???
put x=-c , what's f(-c)??
d?
if x=-c, then denominator becomes 0, which makes f(-c)= finite/zero which is infinity so -c is an asymptote
can you tell e the other asymptote???
-a
*me
X=-a will make numerator zero, what will make the denominator zero?
@amymsmith2121 ????
i don't know. i'm sorry
In the denominator, we have (x+c)(x+d) so when x=-c or x=-d then it'll be zero which will make function f go toward positive or negative infinity, so x=-c and x=-d are the asymptotes of function
ok, i think i understand
Great, did you understand how to find zeros?
when x=-c or x=-d
Zeros of function, when f(x)=0
can you show me an example with real numbers? variables are confusing
Okay. say we have \[f(x)=\frac{(x+2)(x-3)}{(x+4)(x-5)}\] When x=-2 \[f(-2)=\frac{(-2+2)(-2-3)}{(-2+4)(-2-5)}=\frac{0 \times (-2-3)}{(-2+4)(-2-5)}=\frac{0 \times -5}{2 \times -7}=0\] so x=-2 is a zero , if you put x=3 then also f will be zero!!!! so x=-2 and x=-3 are the zeros
Did you understand this?
Gross
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