Question

Determine the parameterized equation
Question #2

Answer 1

you need an initial point, and a vector

Answer 2

the initial point is \((1,1)\) and the vector is\[x=2t\]\[y=t\]\[0\le t\le 1\]so we have\[r(t)=<1,1>+t<2,1>=<1+2t,1+t>;0\le t\le1\]sorry to just give out the answer like that... not my style normally

Answer 3

ohhhhh

Answer 4

I figured I'd just let you tell me if/what you didn't understand

Answer 5

sorry i cldnt write nething b4

Answer 6

I keep getting logged out

Answer 7

I got x=t and y=1/2t

Answer 8

that is the same thing
x=t and y=1/2t
x=2t and y=t
but you must specify an initial point, and the bounds for t
if you have it your way we need \(0\le t\le2\) to get to the point \((2,3)\) from \((1,1)\)

Answer 9

alrighty thanks. I may be back to check the rest

Answer 10

cuz i am a lil iffy on this

Answer 11

I should say that we have the same vector, but they are different sizes
and you forgot to include the initial point and bounds of t

Answer 12

if you have a specific question I can try to help...

Answer 13

so the bounds are 0<t<2?

Answer 14

if you do it your way, yes
if you do it my way, then \(0\le t\le1\)

Answer 15

ok. Thanks Turing and congratz on ur mod status

Answer 16

thanks :)