Question

A=De^(-0.65t)
Find an expression for the amount of drug in the body just after the nth dose has been given.

Answer 1

Do you mind explaining what t is, and how long does it take to apply one does?

Answer 2

*dose

Answer 3

can u little bit elaborate!

Answer 4

Hmm well the only stuff I wrote down about it is
A=De^-0.65t
A=De^-0.65*2t
A=De^-0.65*3t
A=De^-0.65*4t
A=De^-0.65*5t

Answer 5

Suppose the initial dose, D, of a drug is given at time t=0 and that this dosage is repeated at intervals of every T minutes.

Answer 6

dy/dt =-ky

Answer 7

what t represent?

Answer 8

The previous question was
Show that the amount of initial does remaining when the second dose is given is De^-kt

Answer 9

*does t represent

Answer 10

time

Answer 11

so, t/n =T ?

Answer 12

Hmm I'm not sure, I think I'll just ask a classmate that has already done it.

Answer 13

Hmm, I don't have your exact question, with what the unknowns represent, so it is hard to tell.. :S

Answer 14

Thanks for trying :D

Answer 15

wrong group

Answer 16

welcome, sorry that i can't help you :(