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5^2x+1=9^x+1
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solve
if there is no solution state so?
First, lrn2parenthesis please :)
use log or ln
\[5^{2x+1} = 9^{x+1}\], Firstly I suggest you take logs of both sides to give\[\log5^{2x+1}=\log 9^{x+1}\] becomes \[(2x+1)\log5 = (x+1)\log3^{2}\] expand\[2xlog5+\log5=2(x+1)\log3\] collect like terms \[2xlog5-2xlog3 =2\log3-\log5\] and lastly, equate\[x= (2\log3-\log5)/(2(\log3-\log5)\]
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