Question

integral of ( x^2-2x=1)/x dx

Answer 1

No boundaries? If not - just find the antiderivative and add a constant C.

Answer 2

x^(3)/3-x^(2)-x+C

Answer 3

Can you show me how you got that?

Answer 4

\[\int\limits (x^2-2 x-1)/x dx = 1/2 ((x-4) x-2 \ln(x))+c\]

Answer 5

Oh, missed the /x, nvm my answer, hehe

Answer 6

Its x^2-2x+1

Answer 7

You wrote: "x^2-2x=1"

Answer 8

Yes i know i meant to but a +

Answer 9

\[\int x^ndx=\frac{x^{n+1}}{n+1}+C\]

Answer 10

\[\int\limits (x^2-2 x+1)/x dx = 1/2 (x-4) x+\ln(x)+c\]