Question

The figure below shows a bamboo structure.

A right triangle ABC with right angle at C and AB as the hypotenuse. CN meets AB at N at a right angle. The length of AN is 5 feet. The length of AB is 11 feet.

What is the length of CN, rounded to the nearest hundredth? Show all the steps you used to find your answer.

Answer 1

I could really use the help

Answer 2

http://jwilson.coe.uga.edu/emt668/emat6680.folders/brooks/6690stuff/righttriangle/rightday3.html

Answer 3

@Tchan you know the Pythagoras theorem??

Answer 4

yes i do \[a ^{2}+b ^{2}=c ^{2}\]

Answer 5

Good:)
AB=11
AN=5
so
NB=6
Now tell me the value of BC in terms of CN and NB using Pythagoras theorem in triangle NBC

Answer 6

How can i do that if i only have one leg NB

Answer 7

you cant find BC with out CN

Answer 8

Yeah just tell me in terms of NB and CN, just the Pythagoras equation

Answer 9

6^2+CN^2=NB^2??

Answer 10

Good:)
Now tell me AC in terms of AN and NC from the triangle ANC

Answer 11

idk

Answer 12

using Pythagoras theorem!!!!

Answer 13

Dude this is my last question and i am in japan its like 2 in the morning can you just help me out and tell me how to find CN

Answer 14

\[AC^2=AN^2+CN^2\]
so
\[AC^2=5^2+CN^2\]
you made a mistake in the previous
it'd be
\[BC^2=NC^2+BN^2\]
\[BC^2=NC^2+6^2\]
Now in triangle ABC
\[AB^2=BC^2+AB^2\]
so
substitute BC^2 and AB^2 found earlier
\[11^2=NC^2+6^2+CN^2+5^2\]
we get
\[121=2 CN^2+36+25\]
so
\[121=2CN^2+61\]
we have now
\[121-61=2CN^2\]so
\[CN^2=60\]
\[CN=\sqrt{60}\]
CN=7.745

Answer 15

thank you man