Simplify the given expression. square root of negative 64 over open parentheses 7 minus 6 I close parentheses minus open parentheses 2 minus 2 i
words=numbers please :(
ill write it out now
\[\sqrt{-64\div} \left( 7 - 6i \right) - \left( 2- 2i \right)\]
\[\LARGE \frac{\sqrt{-64}}{(7-6i)}-(2-2i)\] do you mean this ?
@cuddlepony there's one "i" after number 6
no its the sqrt of -64 divide by everything else
ahhh ... sweet . Now I see ;) \[\huge \frac{\sqrt{-64}}{(7-6i)-(2-2i)}\] this must be then ;) ... let me try ;)
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAWWWWWWWWWWWWWWWWWWW :@:@:@:@:@:@ F#C#K@NG GOOGLE CRASHED :@ EVERYTHING LOST !! ....
I'll write again .. hold on
oh no :((
??
\[\LARGE \frac{\sqrt{-64}}{(7-6i)-(2-2i)}=\frac{i\sqrt{2\cdot 2\cdot 2}}{(7-6i)+(2i-2)}\] I'll post it by parts... so it would not be lost.. :S
okay thanks!!
it is ..\[\LARGE i \sqrt{4\cdot 4\cdot 4}\]
I'll do it faster I have an idea !!! ... wait.
haha okay
do you see it? .. ... do you have to find imaginary part and real part or only to simplify ? :) LATEX SUCKS ! lol
@mscrosscountry still there?
yes thank you so much!
Glad to help :)
Join our real-time social learning platform and learn together with your friends!