Question

formula to solve gradient of a tangent?

Answer 1

by gradient you mean derivative?
multivariable, single variable, paramaterized...?
could you please be more specific?

Answer 2

to the curve at a point.its a calc question.

Answer 3

can you give the exact question please?

Answer 4

on a table,x=3 ,f(x) =9 and f'(x)=12..in the second part of the q,it says write down the gradient of the tangent to the curve at the point(3,9)

Answer 5

that terminology is foreign to me, let me google it, lol

Answer 6

the answer is 12,but i dont know how though.it it cuz f'(x)= 12 ,and thats at the bottom of the curve?

Answer 7

gradient of a tangent ... i think ... you would get constant. 12 i suppose

Answer 8

yeah, that's sort of what I thought
the "gradient of the tangent line" is the slope of the line, which is the derivative at that point
i.e. f'(x)=12

Answer 9

seems kinda redundant

Answer 10

the question,or my question?

Answer 11

lol ... sure it's quite confusing.
you are given a line ... x is given y = f(x) ... and slope is given ... and gradient of line is const.

Answer 12

the question
I guess it's conceptual:
do you understand that the slope of the tangent line at a point is the derivative at that point?

Answer 13

yeah,saying constant instead of tangent to the curve makes alot more sense..

Answer 14

well the slope of a tangent line is a constant, so....

Answer 15

that terminology is a bit foreign to me =p

Answer 16

that is the gradient ... for a line.

Answer 17

you know the formula\[y-y_0=m(x-x_0)\]right?

Answer 18

sorta,but i just used my gdc instead.

Answer 19

what is that?

Answer 20

graphic display calculator.

Answer 21

*sigh
and this is where overuse of technology kills mathematics...
\[y-y_0=m(x-x_0)\]is the equation of a line that passes through the point \((x_0,y_0)\) with slope=\(m\)

Answer 22

this is algebra stuff, you need to know that this is the equation of a straight line

Answer 23

*one of the equations

Answer 24

o ok.thanks.

Answer 25

after that you can apply this
http://upload.wikimedia.org/wikipedia/en/math/e/9/6/e9632e2216806e86987ce516ad004e24.png

only for dx --> rest of value is zero ... and gradient is vector quantity

Answer 26

when did this site turn into facebook 2.0 =/ theres more talk than there is math problem solving...

Answer 27

Well, all I can say is the gradient at a point is the slope of the line tangent to that point.
It seems you have missed quite a bit so it's difficult to explain.
@experimentX I don't think that is the gradient they are referring to, though it is how I know it as well. I think that the gradient vector is above the level of math that nck93 is doing

Answer 28

there is more teaching than what you may consider solving

Answer 29

well,as in the chat and open questions.alot of them dont have questions pertaining to math sometimes.

Answer 30

may be .. i guess you are right.

Answer 31

if anyone is chatting let me know, it doesn't belong in posts
we are discouraging people who just give answers without explanation if that was what you are referring to by "less solving"

Answer 32

well, i got lot's of complaints for being less explanatory ... lol.

Answer 33

anyway, I won't just give the answer (even though we already have)
@experimentX yes, it's easier to just solve them, but that really doesn't do anything other than show off
We know you have skills, you don't have to prove it ;)

Answer 34

yeah ... i agree. i would love to have lot's of discussion tough ... but only very few people bother.

Answer 35

lol you need vast knowledge on the subject for that,something i dont have with math.

Answer 36

keep trying nck93 ... keep going thats what i say. i'm still just a toddler the field of math is too big ... the more you know the more you know that you do not know. ..lol

Answer 37

although,when it comes to foreign policy,military intervention,military history,psychology and literature,i'm pretty proficient.

Answer 38

lol if your're a toddler,im a fetus..

Answer 39

lol ... :)