Question

Convert the polar equation to rectangular coordinates.


r = 6 cos θ

Answer 1

I got is this correct?
x+y=6

Answer 2

put
\[ r = \sqrt{(x^2+y^2)}\] and
\[ \cos\theta = \frac{x}{\sqrt{(x^2+y^2)}}\]

rest of the work is to simplify

Answer 3

Im not seeing it

Answer 4

did the problem over now i get

(x-3)^2 + y^2 = 6

Answer 5

looks like you got a circle ... though i am not quite sure myself on polar coordinates.

Answer 6

looks like thats right
http://www.wolframalpha.com/input/?i=r+%3D+6+cos+%CE%B8

Answer 7

>>I got is this correct?
x+y=6
----
No. r = 6 cos (theta) is a circle. x + y = 6 is a line.

r = 6 cos (theta)
r = 6 (x/r) Note: x/r is the ratio of the adjacent leg to the hypotenuse (radius)
r/1 = (6x)/r
r^2 = 6x
x^2 + y^2 = 6x
y^2 = 6x - x^2

Answer 8

i got x^2=(y-3)^2=1

Answer 9

@experimentX