What type of quadratic equation is represented in the graph below? Image Link:https://www.connexus.com/content/media/527934-762011-81651-AM-738123731.png A. Non-factorable Trinomial B. Difference of Two Squares C. Perfect Square Trinomial D. Not enough information Im almost positive this is C as well? Is that right?
C. perfect square trinomial ... i suppose
it has only one root ... and this is the case that arise only when there's a perfect square
sorry lost connection there for a sec
that's what I was thinking... Thanks! but I do have another question, but it's kind of long? Do you think you could help me out? I just need someone to check it for me?
Here it is... Part 1: Solve each of the quadratic equations below and describe what the solution(s) represent to the graph of each. Show your work to receive full credit. 0 = x2 + 5x + 6 0 = x2 + 4x + 4 Part 2: Using complete sentences, answer the following questions about the two quadratic equations above. Do the two quadratic equations have anything in common? If so, what? What makes y = x2 + 4x + 4 different from y = x2 + 5x + 6? My Answer: Part 1 x^2 + 5x + 6 = 0 this can be factorised as x^2 + 2x + 3x + 6 = 0 x(x+2) + 3 ( x + 2) = 0 (x+2) * ( x + 3 ) = 0 x = -2 or -3 For x^2 + 4x + 4, it is factorised as x^2 + 2x + 2x + 4 =0 this simplifies to (x+ 2) * (x+2) =0 or (x+2)^2 =0 in both cases, x = -2 Part 2: These to two equation differ by the fact that the second equation is touching the x-axis when graphing, and the first equation is goes through the x - axis which gives it to x - intercepts. Does this sound okay? or should I be more specific?
first part is correct. second part is quite missing something ... they have common root. common root means they are intersecting at the point of common root.
ohh, right... okay ill put that in there. thanks :) so now i this is what I put: These to two equation differ by the fact they have a common root. Therefore, they are intersecting at the point of common root. Also, the second equation is touching the x-axis when graphing, and the first equation is goes through the x - axis which gives it to x - intercepts. is that better? Sorry for the late reply, lost connection again. :/
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