In right triangle ABC, with right angle at C, a= 28 and B= 21 find Sin A/2 In right triangle DEF with right angle at F D= 16 E= 12 find Cos (2E) I don't get it? Do I just do Cos 24?
so its just as simple as I thought it is?
So is it .18?
and .91?
i misread the question - its not sin A but sin A/2 i'll have to think about this one...
you can easily find the measure of sides b and c and angles A by using the trig ratios. and there is a trig identity for sin A/2 which i'd have to look up.
Ah geez I don't have the measure of angle b but side B Can't I just assume those angles are 45 degrees?
And it's also the sides of DEF.
the usual notation is small letters a, b and c are sides (opposite angles A, B and C) so B = 21 means angle B = 21 degrees so is that what the question says or should side b = 21?
so side b = 21 right?
No I was an idiot and typed it all up wrong.
I'm given the sides yes.
I'm sorry I meant. a/ sin A = b/Sin B = c/Sin C
Err no nevermind I don't have side c.
i'm afraid you've lost me moth
Forget everything I said. I was wondering if it was possible to get the correct angle using the law of sines.
is it angle A you want to find?
Yes.
Or I could use the law of cosines to get side c c² = b² + a² - 2ba cosC Then use the law of sines to get the appropriate angle.
you have a right-angled triangle so you dont need to use the sine or cosine rules
What? So this is just as simple as Sin 45/2?
no - i'm assuming you want to find the sine of angle A: |dw:1333743897018:dw|
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