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equation of the tangent to curve y=e^x at x=-1
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differentiate , remembering \[\frac{d(e^x)}{dx} = e^x\] then substitute in x = -1 into dy/dx to get the gradient of the tangent you should get m = e^(-1) = 1/e now use the formula y - y1 = m(x - x1) with x1 as -1 and y1 as e^(-1) = 1/e
yes tht is the answer. I ws about to post
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