Question

A mass is oscillating on a spring with a period of 1.20 s. At t = 0 the mass has zero speed and is at x = 4.85 cm. What is the magnitude of the acceleration at t = 3.30 s?

Answer 1

\[F=ma=-kx\]
So
\[a=-\frac{k}{m}x\]

Find x at t = 3.30s:
\[x=A\cos(2\pi ft)\]

with: f = 1/T

use k/m in the above equation for 'a' from:
\[f = \frac{1}{2\pi}\sqrt{\frac{k}{m}}\]

Answer 2

ok,let me give it a try,thanks

Answer 3

what will be my k?

Answer 4

You don't know k or m, but you can solve for k/m from the last equation.

Answer 5

square root of k/m is the same tin as k^2/m^2 right?
trying to do the algebra

Answer 6

\[\frac{k}{m} = (2\pi f)^2\]

Answer 7

You square both sides, which gets rid of the square root, and leaves you with everything else squared.

Answer 8

is saying my answer is wrong

Answer 9

I don't have a calculator with me, so I can't check your steps. Sorry.

Answer 10

can u use online calculator?

Answer 11

I found one. Give me a minute to compute.

Answer 12

i did (2*3.14*(1/1.20))^2

Answer 13

k/m = 27.4

Answer 14

the system aint accepting my answer

Answer 15

x = 4.63 cm

Answer 16

a = - 126.9 cm/s^2

Answer 17

still wrong

Answer 18

is your answer in m/s^2 rather than cm ??

Answer 19

cm

Answer 20

I don't see an error here. Maybe someone else can find the problem.