Solve |x + 6| = 12. A. 6 B. -18 C. {6, -18} D. No Solution
we get two equations when we have an absolute value, because there are two possibilites
\[|x+6|=12\]implies that either\[x+6=12\]or\[x+6=-12\]
-12=x+6 x+6=12 -12-6=x x=12-6 -18=x x=8
solve each equation separately and you will have your answer
@TuringTest I'm having a doubt ... example: if I have this equation: \[\Large |x-2|>7\] when I start solving, after taking off the absolute value should I change - into + like: -7>x+2>7 ?? :(:( or do I have to leave it minus like it is ?
@Kreshnik 1)please don't cut me off in the future, I had this under control and wanted to \(not\) provide the answer -in answer to your question \[|x-2|>7\]implies that either \[x-2>7\]or\[x-2<-7\]
only if the sign is\[x<y\]can you write\[-y<x<y\](provided that y>0}
sorry, typo* should have been\[|x|\le y\implies -y\le x\le y\]
... and if \[\Large x\neq y\] x=1 y=2 1<2 -2<1<2 I think yes :( @TuringTest I do really apologize for interrupting , It won't happen again !
but\[|x|\ge y\implies x\ge y\text{ or } x\le-y\]
it's fine, no worries ;D I'm just trying to prevent those who would keep trying to avoid explanation, and I think this particular asker is a culprit ;)
ahh... obviously, he doesn't even try to solve those, and I think that will revenge him in the future! ... he won't get nowhere without trying ! ... @TuringTest Thanks for explaining it. I apologize again ;)
Yup, I think so @TuringTest and @kreshnik - I'll take care of that. Btw, great work from both of you here.
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