the 10th term of an arithematic series is 34, and the sum of the first 20 terms is 710. determine the 25th term
\[a _{n}=a _{1}+(n-1)d\]
\[34=a _{1}+(10-1)d\]
dont u use the formula sn = n/2 (2a (n-1)d) For the sum of the arethematic SERIES, NOT SEQUESNCE
@nupursehrawat get here.. and see how it goes ;) ... (we can chat there too. ) http://www.twiddla.com/807035
tell me when you're there ...
@nupursehrawat ... are you there?
@nupursehrawat check this out ...
She told you that you couldn't use that formula.
That's what stumped me. I thought we needed that formula.
now we have... \[\Large a_1=34-9\cdot 3\] \[\Large a_1=7\] Now substitute \[\LARGE a_1=7 \quad \quad d=3\] in this equation... \[\LARGE a_{25}=a_1+(n-1)d\]
look again , she was confused, and asked you if we should use formula of Sn instead of a_n but she forgot this : \[\huge ?\]
I guess you and I are the only ones still interested in the problem.
100% agree !
no im here
My mom Called me SOOOOOOOOORY
Ok then check out link I posted before, Hope that helps , if it doesn't I don't know other way !
It Does Help Thank You Verryyyy MUCH Appreciate It :)
My preasure ... @Mertsj could do this one easily I'm extremely sure, but he thought that you're not allowed to use the formula I used LOL ...
But Its Hard To Understand
What You Did In The Picture
do you know two main formulas of arithmetic sequences ?
yes
do you mind if I ask you to write them for me ?
Sn = N/2 (2a (n-1)D Sn = (a + Tn) Tn = term number a = first number
other formula ?
Its ok I Will ask my teacjer for help Bye
...as you wish !
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