how to solve a problem like this?
Jessica deposits $300 into a savings
account that pays an annual interest rate
of 2%, compounded twice a year. How
much money will Jessica have in her
account at the end of one year?
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OpenStudy (ash2326):
@Suzy you know compound interest?
OpenStudy (anonymous):
no i just want to know the formula
OpenStudy (ash2326):
Let the deposited amount be P (Principal) r = rate of interest
t= time in years
n= no. of times the interest is compounded per year
n=1 for once a year
n=2 for twice a year
the final amount is given as
\[\large A=P\times (1+\frac{r}{n})^{nt}\]
Here we have
P=$300
r=2%=(\frac{2}{100}\)
n=2
t=1
\[Interest=A-P\]
OpenStudy (ash2326):
Sorry
r=2%=\(\frac{2}{100}\)=0.02
OpenStudy (ash2326):
@suzy4321 Can you do it now?
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OpenStudy (anonymous):
306
OpenStudy (ash2326):
This is A or interest???
OpenStudy (anonymous):
A meaning answr yes
OpenStudy (ash2326):
A means final amount!!!
Did you use
Interest= A-P??
OpenStudy (anonymous):
my answer 306.03 is correct
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