Question

A 4.6 kg particle is projected with an initial speed of 4.3 m/s along a surface for which the coefficient of kinetic friction is 0.6. Find the distance it travels given that:a) the surface is horizontal;) the particle moves up a 28 degrees incline;the particle moves down a 28 degrees incline.

Answer 1

use the work-energy theorem\[W=\frac{1}{2}m \left( v_{2}^{2}-v_{1}^{2} \right)\]\[F \Delta x=\frac{1}{2}m \left( v_{2}^{2}-v_{1}^{2} \right)\]Δx is the travel distance

Answer 2

what would v final be?

Answer 3

v final is 0, because the friction reduces its speed