Question

Help me with the attached file :)

Answer 1

@ash2326

Answer 2

@.Sam. @Satellite73 @Diyadiya @experimentX ... Does anyone know this? ... I wish I did, unfortunately I don't.. :( (sorry for disturbing...)

Answer 3

is it hard?

Answer 4

i was here all the time. :)

Answer 5

no.. uhauhauhauhauhauhauh... LOL I do really apologize, I wouldn't ask here if I wanted , I just thought about to help him :( ..

Answer 6

CB seems to be q+p

Answer 7

CD+DA = q

Answer 8

so?

Answer 9

Oo .. again i didn't read the question properly

Answer 10

given that DC = 3p => CD = -3p, put that value and get DA interms of p and q

Answer 11

it's a trapezium

Answer 12

AE = AB + BE = p +kq

Answer 13

for the last part,
DA and AE must be proportional on p and q

Answer 14

i guess that does it.

Answer 15

how do u make them proportional
DC = AE
\[3p+q = p + kq\]
\[3p-p = kq-q\]
\[2p = q(k-1) \]

Now how do we equal to find "K"

Answer 16

k = 1/3 q ... from the first equation

Answer 17

yeah how is it cn u shw me using equations?

Answer 18

I don't think you should really equate, you just have to keep in mind that
combinations of two vectors with proportional coefficient will give you parallel vectors.
Coefficients must be proportional
1 q = 3 p ==> p:q = 1:3

1/3 q = p ==> same must be here

Answer 19

so k = 1/3

Answer 20

must be