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OpenStudy (anonymous):
A sample of a hydrocarbon Contained 4.4g of carbom=n and 2.8g of hydrogen Its molecular formula is 86 what is its empirical formula?
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OpenStudy (anonymous):
So first to find the ration. Carbon mass divided by total mass. Then Hydrogen mass divided by total mass. The answers give you the percentages of mass. Then the percentages divided by molecular mass.
OpenStudy (anonymous):
*ratio
OpenStudy (anonymous):
C- 0.61111/12 H-0.38888/1
OpenStudy (anonymous):
|dw:1333907456914:dw|
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