Question

integral of 1/( x^2 +6x +9) dx

Answer 1

does it help to know that \(x^2+6x+9=(x+3)^2\)?

Answer 2

(x+3)^-2

Answer 3

\[\int \frac{1}{x^2+6x+9} dx\]
If you notice
\[x^2+6x+9\]
this is
\[(x+3)^2\]
so we have
\[\int \frac{1}{(x+3)^2} dx\]
or
\[\int (x+3)^{-2} dx\]
Can you solve now?

Answer 4

i guess it does!

Answer 5

YEs thanks

Answer 6

its -1/(x+3)+c

Answer 7

Yeah great work:D