Question

Find parameter a values , in which the equation... will type it... has (5-a+3|a-1|)/4 solutions.

Answer 1

\[(10a-29)*27^x+(11-3a)*9^x-(7a-17)*3^x+1=0\]

Answer 2

5

Answer 3

that equation should have ???

Answer 4

Find the values of a so that it would have (5-a+3|a-1|)/4 solutions.

Answer 5

what sign is after 3 ?

Answer 6

Absolute value

Answer 7

looks like 5

Answer 8

this wann to be 3/a ?

Answer 9

3*|a-1|

Answer 10

since it's cubic equation, it has 3 roots at most ...

Answer 11

- so than you will have two cases for Ia-1I
1. when Ia-1I = a-1
2. ---- Ia-1I = - (a-1)

Answer 12

can you continue it ?

Answer 13

I don't think so.

Answer 14

ErkoT: you need to use the hints that experimentX and jhonyy9 gave you.
so we know this is a cubic equation - therefore there are 3 solutions.
therefore, we know:\[\frac{5-a+3|a-1|}{4}=3\]solve this for two cases, one where a >= 1 and the other where a < 1.

Answer 15

Alright. I'll try.