Question

My original function is f(x)=2x^3-3x. If h is the inverse function then h'(y)= How do i solve this? I switched x and y and got confused

Answer 1

f'(x) = 6x^2 -3
derivative of inverse is 1/f'(x)
so h' = 1/(6x^2 -3)

Answer 2

Does this work every time or only in special cases?

Answer 3

every time when f' is not equal 0

Answer 4

okay thanks alot!!! :)

Answer 5

welcome

Answer 6

This site might help you: http://en.wikipedia.org/wiki/Inverse_functions_and_differentiation

Answer 7

Thank you!!

Answer 8

yw

Answer 9

Yes, don't ever try to find the inverse and derive; it is slower and inefficient. And, sometimes it's not very easy (for example, if your function was a polynomial you didn't know how to solve, how would you isolate the variables?)