My original function is f(x)=2x^3-3x. If h is the inverse function then h'(y)= How do i solve this? I switched x and y and got confused

Question

anonymous · Answer

f'(x) = 6x^2 -3
derivative of inverse is 1/f'(x) 
so h' = 1/(6x^2 -3)

anonymous · Answer

Does this work every time or only in special cases?

anonymous · Answer

every time when f' is not equal 0

anonymous · Answer

okay thanks alot!!! :)

anonymous · Answer

welcome

asnaseer · Answer

This site might help you: http://en.wikipedia.org/wiki/Inverse_functions_and_differentiation

anonymous · Answer

Thank you!!

asnaseer · Answer

yw

inkyvoyd · Answer

Yes, don't ever try to find the inverse and derive; it is slower and inefficient. And, sometimes it's not very easy (for example, if your function was a polynomial you didn't know how to solve, how would you isolate the variables?)