Question

NEED HELP!!
Will post image

Answer 1

Choice D. The scale between the large parallelogram and the small one is 2:1

Answer 2

Thank you :] can you explain how?

Answer 3

... note that you have:

S(7,-1) T(5,-3)

A(8,4) D(7,3)

now we need to find the distance between dots...
let's start from...
S(7,-1) T(5,-3)

\[\Large d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\]
\[\Large d=\sqrt{(5-7)^2+(-3-(-1))^2 }\]
\[\Large d=\sqrt{4+4 }\]
\[\Large d=\sqrt{4\cdot 2 }\]
\[\Large d=2\sqrt{ 2 }\]

Let's find now for ..
A(8,4) D(7,3)

\[\Large d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\]
\[\Large d=\sqrt{(7-8)^2+(3-4)^2}\]
\[\Large d=\sqrt{(-1)^2+(-1)^2}\]
\[\Large d=\sqrt{2}\]

so distance between
S(7,-1) T(5,-3) is \[\Large d=2\sqrt2\]
and
A(8,4) D(7,3) is \[\Large d=\sqrt2\]

so relation is \[\LARGE 2:1\]
does this help? :) @zeecho

Answer 4

Kreshnik is totally right.