What is the pH if 100 mL of 1.00 M NaOH is added to the buffer in the previous problem? (Previous problem was: If 30.0 grams of solid NaF is placed in 1.00 liter of a 1.00 M HF solution, what is the pH of the buffer solution? answer is 3.38)
ok so i'm not sure if i've got this right so i hope someone will check it. I would find both the moles of NaOH and H+. The h+ moles can be found from the pH. There are significantly more moles of OH then H so we know the ph will be much greater than 7 becuase it will be basic. I would then subtract the amount of moles of hydronium from the amount of moles of OH and divide by the total volume which is 1.1L. Now I have pOH. 14-pOH = pH. It should be somewhere around 12.96. I fear this is incorrect.
Thank you for time and help. Also, love your username!
No problem and thanks
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