Prove that in any isosceles triangle, the median drawn from the vertex angle is the perpendicular bisector of the opposite side.
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Given :Triangle ABC with AB = AC and median AD Prove: AD is the perpendicular bisector of BC 1. AD is a median 1. Given 2. BD is congruent to CD 2. Definition of median 3. AD bisects BC 3. Definition of bisect 4. AD is congruent to AD 4. Reflexive 5. Triangle ABC is isosceles. 5. Given 6. AB is congruent to AC 6. Definition of isosceles triangle 7. Triangle ABD is congruent to triangle ACD 7. SSS 8. Angle ADB is congruent to angle ADC 8. CPCTC 9. m<ADB =m<ADC 9. Definition of congruent angles 10. m<ADB +m<ADC = 180 10. Definition of straight angle 11. 2m<ADB = 180 11. Substitution 12. m<ADB = 90 12. Division property of equality 13 AD is perpendicular to BC 13. Definition of Perpendicular
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