Question

int (tan)^6 dx

Answer 1

int? are you programming.

Answer 2

Elaborate more on the question if possible.

Answer 3

you need to integrate,
right???

Answer 4

They could take a derivative as well...

Answer 5

integrate

Answer 6

You would first break it up, so you have (sec^2 x -1)(tan^4) (because tan^2 = sec^2 -1)
Next, you would distribute giving you sec^2(tan^4) - tan^4
We can use u-sub for the first part giving us tan^5/5 and not for the second part...
Break tan^4 up again into tan^2(sec^2 -1)... distribute and we have tan^2(sec^2) - tan^2
use u-sub for the first part and we have tan^3/3 and for the second part we break tan^2 into sec^2 -1 again which is tan -x
You should end up with:
\[\tan ^{5}/5 - \tan ^{3}/3+tanx-x+C\]
I believe that is correct, but double check it.

Answer 7

what a daring person.

Answer 8

I agree, you sir get a medal.

Answer 9

thanks