Question

how do you complete the square for 4y^2-4y-35? with out factoring

Answer 1

http://en.wikipedia.org/wiki/Completing_the_square
check out the non-monic case
but that seems like an awkward way to solve this particular equation

Answer 2

yea i can do it when i factor out the 4 but then i need to put it in the non factored form so that i put it in the derivates of tan-1(x)

Answer 3

(2y-1)^2 - 36 ?

Answer 4

how did you get that? can you pls show me the steps?

Answer 5

\[4y^2-4y-35=0\]
\[( ? y - ? )^2 = 35\]
\[(2y-1)^2-1=35\]
\[(2y-1)^2-36=0\]

Answer 6

thanks :)