Question

write the following square root in the form a√b= where a and b are integers and b has the least value possible.√63=

Answer 1

\[\LARGE \sqrt{63}=\sqrt{9\cdot 7}=\sqrt9 \cdot \sqrt7=3\sqrt7\]

Answer 2

Thanks Kreshnik. Have one more question for you to help me with if you can.

Answer 3

Find the prime factorization of 55^5*65*9^15

Answer 4

why don't you post it on wall... what if I don't know it ?

Answer 5

auff...

Answer 6

prime of 120
does it mean:
60*2
30*2*2
15*2*2
... ??

Answer 7

Ok thnaks

Answer 8

no no .. wait, that's not the answer :F lol I was just asking what does prime mean. Because I'm not american I don't understand well enough sometimes :( @dog1985

Answer 9

Ok. Hold on I have the defintion for prime factor.

Answer 10

@dog1985 I hope it's not what I think it is.. do you know that 55^5*65*9^15 is going to be a very LOOOONG... number ! ? :O

Answer 11

It gave me 4 to choose from.

A. 3^15*5^6*11^5*13
B. 3^30*5^6*11^5*13
C. 3^30*5^6*11*13
D. 3^30*5^5*11^5*13

Answer 12

\[\LARGE 9^{15}=\left(3^2\right)^{15}=3^{30}\] so let's eliminate option A. :) ... now let me think ;)

Answer 13

Ok

Answer 14

\[\LARGE 55^{5}=(5\cdot 11)^5=5^5\cdot 11^5\]
so we have..
\[\LARGE 55^5\cdot 65\cdot 9^{15}\]
\[\LARGE (5\cdot 11)^5\cdot 65\cdot 9^{15}\]
\[\LARGE 5^5\cdot 11^5\cdot 65\cdot 3^{30}\]
now we have..
\[\LARGE 65=5\cdot 13\] so..
\[\LARGE 5^5\cdot 11^5\cdot (5\cdot 13)\cdot 3^{30}\]
\[\LARGE 5^{5+1 }\cdot 11^5\cdot 13\cdot 3^{30}\]
\[\LARGE 5^{6 }\cdot 11^5\cdot 13\cdot 3^{30}\]

so option B looks to me correct since it is..
3^30*5^6*11^5*13
with latex it looks..
\[\LARGE 3^{30}*5^6*11^5*13\]
SO i GUESS THEY ARE THE SAME ;) OPTION B DEFINITELY !

Answer 15

You helped me understand it better than I did before. Thanks for your help.

Answer 16

My pleasure :) ... You're welcome ;)