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Determine the function f satisfying the given conditions. f'(x)= e^(x/3) f(0) = 4 f(x) = A e^(Bx) + C, b= c=
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i found A= 3
integrate the f'(x)
that will be 3e^(x/3) + C
f(0) = 3e^(0/3) + C 4 = 3 + C or, C = 1, Ans: f(x) = 3e^(x/3) + 1
b= 1/3?
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or just 3
f(x) = 3e^(x/3) + 1 is the final answer.
B would definitely equal to 1/3 by comparison
thanx
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