Question

PLEASE HELP ME ON THE VERGE OF TEARS

Answer 1

use logrithms to solve

Answer 2

Dont you think i would if i knew how to

Answer 3

Take the ln of both sides
then apply the rule

ln(x^(y)) = yln(x), to solve for the exponent

Answer 4

so ln(3^(-2x)) = ln(4)
-2xln(3) = ln(4)
-2x = ln(4)/ln(3)

Answer 5

3^(-2x) = 4 (take log of both sides)
log(3^(-2x)) = log(4) (log(a^b) = blog(a))
-2x = log(4)/log(3)
x = (-log(4))/(2log(3))
x = (-log(4))/(log(9))
x = -0.631

Answer 6

x = -ln(4)/2ln(3)

Answer 7

= -0.63

Answer 8

I recommend reviewing the rules of logrithms here i will post them for you

Answer 9

No more tears now hopefully :)

Answer 10

could i apply that to

Answer 11

ALso note that ln is just log_e
and

log_10(x) = y
is the same as
10^(y) = x

Answer 12

yes you can apply these rules to any exponent try to apply it and i will tell you if you did it right

Answer 13

I wont do your homework for you but I will teach you the concepts you need to solve these with. This stuff is easy once you get it trust me.