Apply the quadratic formula to find the roots of the function and then graph it........ f(x) = x^2 - 4
quadratic formula: (-b±sqrt(b^2-4ac))/(2a) where ax^2+bx+c
so in this case, a=1, b=0, and c=-4 plugging it in, we get \[(-0±\sqrt{0^2-4(1)(-4)})/(2(1))\]
so the first root is \[+\sqrt{16}/2=2\] and the second root is \[-\sqrt{16}/2=-2\]
Thank you
you're welcome!
I just really wish I understood any of that...lol............Oh well, it was worth a try...
haha okay do you know the quadratic equation?
formula*
picture in your head a 43 year old woman who only managed to squeak through basic and advanced algebra, I am now teetering the line in the college algebra for the second time and it does not look good, I have been able to figure out some of this stuff but the quadratic might as well be in ancient script for all I understand of it
I can handle the factoring, but the basic quadratic and the completing the square are next to impossible to understand unless you are a mathmatician, I'm a graphic designer....
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