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Mathematics 17 Online
OpenStudy (anonymous):

URGENT, HEAT EQUATION! Come in if you know your Deferential equations :)

OpenStudy (anonymous):

This is the question, I have solved it but I need someone to double check my solution. Question: Find the temperature u(x, t) in a rod of length L if the initial temperature is f (x) throughout and if the ends x=0 and x=L are insulated. F(x)= x, 0<x<1 and the length of the rod is L=2 0, 1<x<2 Solution: For an insulated rod the solution X(x,t)=\[a_{o}/2 + \sum_{n=1}^{\infty} B_{o} \cos (n \pi )x/L * e^-{n^2 \pi^2\alpha^2} \] I found a_o= 1 and Bn= \[({-2/n \pi}* \sin (n \pi/2) +(2/n \pi)^2 \cos (n \pi/2) - (2/n \pi)^2)\] then just plug in the coefficients into the sum. I am just not sure if these are the correct values for the ao and Bo coefficients.

OpenStudy (anonymous):

yeh guys anybody knows how to do this kind of question?

OpenStudy (anonymous):

Is this fourier Series?

OpenStudy (anonymous):

umm we skipped over it i think

OpenStudy (anonymous):

either way i cheated my way thru series so i dont know nething

OpenStudy (anonymous):

well yes sort of, if you are a math major then you prolly did not learn the heat equation, it is more on teh applications side of mathematics.

OpenStudy (anonymous):

iight cool, i think i got the right solution.. but even if someone decided to help, the solution is long.. lol so i think even if ppl know the answer they wouldnt wnan ahelp out haha

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

ok i think amma leave, this os is useless haha.. if anybody know the answer please help

OpenStudy (anonymous):

bump ur question

OpenStudy (anonymous):

yeh i am just waiting for that, 6 more minutes.

OpenStudy (anonymous):

@JamesJ @FoolForMath @myininaya @TuringTest D:

OpenStudy (anonymous):

hahaha you are the best

OpenStudy (anonymous):

I love getting free medals for bothering other people, while not actually answering the question.

OpenStudy (anonymous):

lol... as long as you are tryna help

OpenStudy (anonymous):

@fretje

OpenStudy (anonymous):

ok am off to study and will be back later on, hopefully will come back and find something useful, see you all!

OpenStudy (anonymous):

@Hero

OpenStudy (anonymous):

Cheers, yo.

hero (hero):

Sorry, I don't really know this, but I can get the solution for it.

OpenStudy (anonymous):

"He's not the Hero Openstudy needs right now, but he's the Hero it deserves." - Batman

hero (hero):

I doubt that Batman said that.

OpenStudy (anonymous):

Let yourself be educated. http://www.youtube.com/watch?v=oL7PSlUuWPs Batman's history is important.

hero (hero):

I'm pretty sure he said nothing about Open Study

OpenStudy (anonymous):

Ehh, details.

OpenStudy (anonymous):

@hero if you can get the solution for it please do so, thanks

OpenStudy (apoorvk):

Lol @badreferences

OpenStudy (anonymous):

Building a time machine?:o

hero (hero):

Anyone who feels like posting a solution should post it. I'm at the point where the more difficult the question, the more I feel like being compensated for my time.

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