Question

need help finding this derivative without the quotient rule.

-7t^3 + 3/(t^3) - 3/(3rdrt(t))

Answer 1

is this the function:

\[-7t^3 + \frac{3}{t^3} -\frac{3}{\sqrt[3]{t}}\]

Answer 2

or this :
\[\LARGE -7t^3+\frac{3}{t^3}-\frac{3}{3\sqrt t}\] ?

Answer 3

then use difference quotient or you can say that first principle.

Answer 4

if quotient rule is not the choice then use above specified rule.

good luck.

Answer 5

yea eig that is the correct equation

Answer 6

\[f(x) = -7t^3 +\frac{3}{t^3} -\frac{3}{\sqrt[3]{t}} = -7t^3 +3t^{-3} -3t^{-\frac{1}{3}} \]

Answer 7

differentiate the normal way ax^n goes to nax^(n-1)

Answer 8

the only confusion i had was converting fractions into exponents. if its 3/ (t^3 that just becomes 3t^-3?

Answer 9

yes

Answer 10

and obviously the other is 1/3 because of the root. Thanks very much that was my only confusion

Answer 11

no problem :) happy mathsing