Question

in the diagram below of triangle ABC, CD is the bisector of angle BCA, AE is the bisector of angle CAB and BG is drawn.

Answer 1

can anyone help me ?

Answer 2

look at the attachment

Answer 3

so this means that G is the incentre. so BG is also an angle bisector, since all 3 angle bisectors are concurrent at the incentre. so angleDBG = angle EBG

Answer 4

that makes sense thank you could you help me on a geometry proof.

Answer 5

yeah shoot!

Answer 6

just look at the attachment

Answer 7

can u help me ?

Answer 8

okay
In tri.LSG and tri.HFA
angleHFS=angleLSF ....{alternate interior angles of a parallelogram are equal)
FH=SF (opposite sides os a parallelogram are equal and parallel)
angleLGS=angleFAH (right angles, given)

hence, tri.LSG and tri.HFA are congruent (by AAS congruency)

Answer 9

thank you so much ! could you help me with another proof ?

Answer 10

yeah sure will try! post it separately though, as it makes it easier. :)

Answer 11

do you mean open a new question

Answer 12

yes.

Answer 13

okay will you help me with it ? I will do it right now

Answer 14

yeah toldya i will.