what is the period, in seconds, of a simple pendulum of length 5 meters?use the gravitational constant g=9.8 m/s^2 and round your answer to two decimal places

Question

ujjwal · Answer

$$T=2\Pi \sqrt{l/g}$$ where T is time period, 
l is length of pendulum
g is gravitational constant..
so by calculation, T=4.48 sec

anonymous · Answer

http://answers.yahoo.com/question/index?qid=20110320160255AAtqHyV

shayaan_mustafa · Answer

$$\large T=2\pi \sqrt{\frac{l}{g}}$$$$\large T=2\pi \sqrt{\frac{5}{9.8}}$$$$\Large T=4.48s$$