Question

what is the period, in seconds, of a simple pendulum of length 5 meters?use the gravitational constant g=9.8 m/s^2 and round your answer to two decimal places

Answer 1

\[T=2\Pi \sqrt{l/g}\] where T is time period,
l is length of pendulum
g is gravitational constant..
so by calculation, T=4.48 sec

Answer 2

http://answers.yahoo.com/question/index?qid=20110320160255AAtqHyV

Answer 3

\[\large T=2\pi \sqrt{\frac{l}{g}}\]\[\large T=2\pi \sqrt{\frac{5}{9.8}}\]\[\Large T=4.48s\]