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Mathematics 17 Online
OpenStudy (anonymous):

Simplify. Assume that all expressions under radicals represent nonnegative numbers √36x^4y^10

OpenStudy (anonymous):

can you factor 36 into its primes?

OpenStudy (anonymous):

you mean 6.6 ?

OpenStudy (anonymous):

thats a start, but 6 isn't prime

OpenStudy (anonymous):

what's a prime?

OpenStudy (anonymous):

a number that cannot be divided evenly by another number (just 1 and itself) 2,3,5,7,11,13...

OpenStudy (anonymous):

6.6 would work (in this case) but I want to show you how I do these a way that works for all of them

OpenStudy (anonymous):

Like 4√9

OpenStudy (anonymous):

I look at that stuff as: 36x^4y^10 = 2.2.3.3.x.x.x.x.y.y.y.y.y.y.y.y.y.y two 2s two 3s four Xs and ten Ys

OpenStudy (anonymous):

then, to get the square root down to size, pull out as many pairs as you can

OpenStudy (anonymous):

is this helping or confusing?

OpenStudy (anonymous):

Both

OpenStudy (anonymous):

well there is one pair of 2s so we have 2√3.3.x.x.x.x.y.y.y.y.y.y.y.y.y.y

OpenStudy (anonymous):

then a pair of 3s 2.3√x.x.x.x.y.y.y.y.y.y.y.y.y.y

OpenStudy (anonymous):

then two pairs of Xs 2.3.x.x√y.y.y.y.y.y.y.y.y.y and five pairs of Ys 2.3.x.x.y.y.y.y.y√1

OpenStudy (anonymous):

so now I count and see 6 x^2 y^5 (and nothing left under the radical)

OpenStudy (anonymous):

I multiply all the numbers I could pull out, and count the letters to get the exponents just another way to look at it... hope I didn't confuse you too much

OpenStudy (anonymous):

Is √36x^4y^10=6 x^2 y^5

OpenStudy (anonymous):

it should be, what do you get when you square it?

OpenStudy (saifoo.khan):

@jupiter , you are correct.

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