Simplify. Assume that all expressions under radicals represent nonnegative numbers √36x^4y^10
can you factor 36 into its primes?
you mean 6.6 ?
thats a start, but 6 isn't prime
what's a prime?
a number that cannot be divided evenly by another number (just 1 and itself) 2,3,5,7,11,13...
6.6 would work (in this case) but I want to show you how I do these a way that works for all of them
Like 4√9
I look at that stuff as: 36x^4y^10 = 2.2.3.3.x.x.x.x.y.y.y.y.y.y.y.y.y.y two 2s two 3s four Xs and ten Ys
then, to get the square root down to size, pull out as many pairs as you can
is this helping or confusing?
Both
well there is one pair of 2s so we have 2√3.3.x.x.x.x.y.y.y.y.y.y.y.y.y.y
then a pair of 3s 2.3√x.x.x.x.y.y.y.y.y.y.y.y.y.y
then two pairs of Xs 2.3.x.x√y.y.y.y.y.y.y.y.y.y and five pairs of Ys 2.3.x.x.y.y.y.y.y√1
so now I count and see 6 x^2 y^5 (and nothing left under the radical)
I multiply all the numbers I could pull out, and count the letters to get the exponents just another way to look at it... hope I didn't confuse you too much
Is √36x^4y^10=6 x^2 y^5
it should be, what do you get when you square it?
@jupiter , you are correct.
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