During the production of sulphuric acid by the Contact process, sulphur
dioxide is converted to sulphur trioxide according to the equation:
SO2(g) + O2(g) - 2SO3(g) Δ H = -285.8kJ/mol
Calculate the heat energy released in the production of one tonne (1.00x106 g)
of sulphur trioxide gas.

How do I do a question like this?

Question

During the production of sulphuric acid by the Contact process, sulphur
dioxide is converted to sulphur trioxide according to the equation:
SO2(g) + O2(g) -> 2SO3(g) Δ H = -285.8kJ/mol
Calculate the heat energy released in the production of one tonne (1.00x106 g)
of sulphur trioxide gas.

How do I do a question like this?

anonymous · Answer

Look at the units. It says KJ per mol. You should be thinking " I love mols and I love grams! I also know how to convert between the two! If I have the amount of energy produced for every mole and I can figure out the moles from the grams I have, then this is $$\Huge{Easy \ peasy \color{yellow}{\ lemon} \ squeasy!}$$

anonymous · Answer

$$n = \frac{mass}{molecular formula}$$

$$n = \frac{106g}{32+3(16)g/mol}$$

=1.325 moles

285.8 KJ per mole = so multiply

anonymous · Answer

@thushananth01 I'm pretty sure he means$$1.00\times 10^6g$$

anonymous · Answer

(1.00x106 g) he has mentioned it like this...anyway if so he would understand how to substitute the values:)

anonymous · Answer

One tonne means$$1.00 \times 10^6$$ silly goose.