Question

Solve. x^2 + 8x + 25 = 0

Answer 1

I'm pretty sure this is going to end up being an imaginary solution

Answer 2

looks like it 4 +- 3i

Answer 3

\[\frac{-b \pm \sqrt{b^{}-4ac}}{2a}\] why cant v use this..

Answer 4

offcourse you can buddy

Answer 5

nope i dont think...maybe the equation is wrong...

Answer 6

why not you can

Answer 7

try and c :)

Answer 8

just you'll get a negative radical... so you'll need complex number notation

Answer 9

\[(-8+-\sqrt{64-4\times25})\div2\times1\]

Answer 10

may you are not familiar with complex numbers

Answer 11

then the solution is undefined

Answer 12

it's not a great deal

Answer 13

square root of negative numbers can be evaluated by defining anew number called IOTA denoted by i (refer the answer given by campell you can see an i there ) this i is nothing but square root of -1,
\[\sqrt{-1}=i\]
so you can modify \[\sqrt{-9}=\sqrt{9}\times \sqrt{-1}\]
but we already know that \[\sqrt{-1}=i\]
so \[\sqrt{-9}=\sqrt{9}i=3i\]