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\[x={3 \over 4}\pi-\sin x\]The equation has one root. Verify by calculation that the root lies between 1.3 and1.5.
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can you just say f(x) = (3/4)pi - sinx - x and find f(1.3) and f(1.5). if the signs are different then a root must exist between x=1.3 and x=1.5
What do you mean if the signs are different?
Oh, I understand. Don't worry. Thank you!
if f(1.3) is, say, positive, and f(1.5) is negative then that proves there must be a root between these two x values.
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