Question

Determine the function f(x) satisfying the given conditions.


f''(x) = 0
f'(5) = 1
f(4) = -2

Answer 1

they want me to find and f'(x) and f(x)

Answer 2

f''(x)=0 means your function is not going to be of higher grade than 1.
From this you can assume that your function can be written as f(x)=ax+b
f'(x)=a

Answer 3

so it would be f(x)= x+5 and f'(x)=0

Answer 4

right?

Answer 5

If you df(x)/dx you have to remember the rules of derivatives.

Answer 6

f'(x) when f(x) = x+5 would be 1 not zero

Answer 7

f'(x)=x^0 --> 1

Answer 8

am i supposed to find the antiderivative?

Answer 9

Is this 3 problems, or are you saying one function to meet the three different conditions aobve??

Answer 10

You have the function f(x), to get f'(x) you just derive f(x).

Answer 11

just 1 problem radar

Answer 12

f'(x) when x^0 is not 1,
x^0=1
f' x^0=0 as it is a constant.

Answer 13

so the function is f(x) is x-2?

Answer 14

so the deriv is 1

Answer 15

Is the first one asking for f'' like f double prime, derivative of the derivative?

Answer 16

no just the first deriv

Answer 17

Well the derivative of any constant is 0 as there is no "change" Let me think how the next two conditions play into this!?

Answer 18

this is the format they want for f(x) = ax^2+bx+c

Answer 19

Really?

Answer 20

Because that does not go together with (f''(x) = 0).

Answer 21

i just tried a previous problem: Determine the function f(x) satisfying the given conditions.

Hint: To answer this question and the next one, think in terms of doing two successive antiderivatives.

f''(x) = 16
f'(0) = 7
f(0) = 4
answer: f(X)=8x^2+7x+4

Answer 22

If you got a different question please post a new question.

Answer 23

no this just an example

Answer 24

Try this: f(x)= (1/2)( x^2) - (1/4)( x^2)

Answer 25

You could use the form f(x)=ax^2+bx+c, that just means a has to be 0 in your example.

Answer 26

and you'll get f(x)=bx+c which is basically the same thing as f(x)=ax+b

Answer 27

f' would be !!! never mind, back to the drawing board lol

Answer 28

i think f'(x) has to be a constant. so f'(x)=C for some value of c.

Answer 29

f''(x)=0 --> f(x)=bx+c --> f'(x)=b
f'(5)=1 --> f'(5)=1 --> b=1
f(4)=-2 --> f(4)=4+c=-2 --> c=-6
f'(x)=1
f(x)=x-6

Answer 30

yes thats right

Answer 31

From what you listed as a previous example.
The first one is a double derivative f"
The second one is a single derivative
The third one is the function itself. Now look at it that way.

Answer 32

ok so u have to find 2nd deriv then work your way down to the function

Answer 33

its all in reverse! lol

Answer 34

That is what it appears to be, and the function 8x^2+7x+4 convinces me.

Answer 35

ok thanx

Answer 36

Hopefully your text will show you the procedure to do that.....It does not seem to be a trivial task.