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Mathematics 19 Online
OpenStudy (anonymous):

consider the function f(x)= sqrt(x^2 + 9) - x f(x) is increasing on the interval ? f(x) is decreasing on the interval? f(x) is concave up on the interval ? f(x) is concave down on the interval ? f(x) has a horizontal asymptote y=?

OpenStudy (rogue):

Use the first derivative to see where it is increasing or decreasing. If it is positive, f is increasing; if it is negative, f is decreasing. Use the second derivative to see where it is concave up and down. If it is positive, f is concave up; the opposite if not. The infinite limit tells you f has a horiz asymptote of y = 0.

OpenStudy (anonymous):

so take the first derivative, graph it and see where its increasing?

OpenStudy (rogue):

- Take derivative. - Set derivative = 0. Solve for x. - See the sign of the derivative between the intervals of where x = 0 and +/- inf. - If the sign of the derivative is positive on the interval, then f is increasing on the interval. The opposite for negative.

OpenStudy (anonymous):

i cant get a solution for the derivative equal to zero

OpenStudy (rogue):

Then the derivative is always positive or negative?

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