Question

The velocity function is v(t)= -t^2+5t-6 for a particle moving along a line. Find the distance traveled.

Answer 1

I already got the displacement to be -67.5
I just need the distance traveled

Answer 2

differentiate with respect to t

Answer 3

can you work it out?

Answer 4

\[\frac{dv}{dt}=\frac{d(-2t ^{2})}{dt}+5\frac{d(t)}{dt}-\frac{d(6)}{dt}\]\[x=-4t+5\]it your required.

Answer 5

so now what

Answer 6

?

Answer 7

Can someone please help me?

Answer 8

Distance travelled = \(\large \int_{t_1}^{t_2}V(t)dt\)

Answer 9

damn.. i did opposite.. @anthonys it is acceleration. yes yes.. you must integrate to find distance.

Answer 10

first put v(t)=0 you will get the time when it stops
then integrate v(t) and put the value of t
you will get your answer

Answer 11

@experimentX thnx for correction.

Answer 12

happens sometime ... happens to me all the time.