The velocity function is v(t)= -t^2+5t-6 for a particle moving along a line. Find the distance traveled.

Question

anonymous · Answer

I already got the displacement to be -67.5
I just need the distance traveled

shayaan_mustafa · Answer

differentiate with respect to t

anonymous · Answer

can you work it out?

shayaan_mustafa · Answer

$$\frac{dv}{dt}=\frac{d(-2t ^{2})}{dt}+5\frac{d(t)}{dt}-\frac{d(6)}{dt}$$$$x=-4t+5$$it your required.

anonymous · Answer

so now what

anonymous · Answer

?

anonymous · Answer

Can someone please help me?

experimentx · Answer

Distance travelled = $\large \int_{t_1}^{t_2}V(t)dt$

shayaan_mustafa · Answer

damn.. i did opposite.. @anthonys it is acceleration. yes yes.. you must integrate to find distance.

anonymous · Answer

first put v(t)=0 you will get the time when it stops
then integrate v(t) and put the value of t 
you will get your answer

shayaan_mustafa · Answer

@experimentX thnx for correction.

experimentx · Answer

happens sometime ... happens to me all the time.