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Simplify -15w^0u^-1 ----------- 5u^3
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\[-15w ^{0}u ^{-1}\div5u ^{3}\]
ok so first of all \(w^0=1\)
so now we have \[\frac{-15u^{-1}}{5u^3}\]
Now we have this formula \[\large \frac{x^m }{x^n}=x^{m-n}\]
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Can you solve now ?
@hogie
\[\large \frac{-15u^{-1}}{5u^3}= \frac{-3u^{-1}}{u^3}= -3u^{(-1-3)}\]
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