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assume the probability of getting head from a biased coin is 0.35. what would be the probability that out of 100 randomly toss, at least 22 of them are head ?
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do 0.35 to the power of 22 and get 9.321x10^-11
to get the percentage multiply the answer by 100 and get 9.321x10^-9 % of getting 22 heads
.... and I don't think it's the correct answer.
why not? o-0
from your method, then out of two toss least one of them is head would be 0.35^1 which is 0.35 though the correct answer would be 0.8225
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ohh wait i didnt see the 100 tosses... sorry
wait then it should be 7.7% chance cause 22 has to at least be head and there is a 35% chance of it being heads so its (22/100) x (35/100) which equals =0.077
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